I can find the slope and the yintercept using both slopeintercept and
Slope And Point To Standard Form. (y − 3 10) = − 1 15(x − 1 2). In this equation, `m` is the slope and ` (x_1, y_1)`.
Slope = y2 −y1 x2 −x1 0 − 3 10 5 − 1 2 − 3 10 9 2 − 3 10 ⋅ 10 9 2 ⋅ 10 −3 45 − 1 15 point slope : In this equation, `m` is the slope and ` (x_1, y_1)`. (y − 3 10) = − 1 15(x − 1 2).
In this equation, `m` is the slope and ` (x_1, y_1)`. In this equation, `m` is the slope and ` (x_1, y_1)`. (y − 3 10) = − 1 15(x − 1 2). Slope = y2 −y1 x2 −x1 0 − 3 10 5 − 1 2 − 3 10 9 2 − 3 10 ⋅ 10 9 2 ⋅ 10 −3 45 − 1 15 point slope :
